Defeating a dragon earns both a treasure and an experience point. Treasures not used by game's end are worth an experience point each and two of them, the town portal and the dragon scales can be worth more. At the end of three delves, the player with the most experience wins. The game takes 5 to 10 minutes per player.
Now all of that would be quite enough adventure for the cost of this game, but there's still more.
The game comes with eight base set hero characters. Each card represents who the player is during the game. Each hero has a novice side and an expert side. After accumulating five experience points, the player may flip the card to the experienced side. Each side of the hero has both a specialty and an ultimate ability. The specialty can be used at any point when it would make sense to use that ability but the ultimate can only be used once per delve or a maximum of three times per game. Each of those abilities are unique to each hero and it adds a lot of flavor and strategic planning to the game.
“There is another hero expansion pack being finalized at the moment and I've already designed a bigger expansion next year,” said Darden. “There are several other expansions on the drawing board, and the success of Dungeon Roll will determine when/if those see the light of day.”
Dungeon Roll is easily the best $15 I ever spent on a game. The full retail price will be $20 and it will still be the best $20 you will spend. The game will entertain one to four players, though with four I would suggest a second copy of the game so that each player is either delving or roll the dungeon dice. It makes the length of the game shorter and removes down time for all players.
Dungeon Roll will be available this coming week at GenCon with a special price of $15 on Thursday. As a show special, the first hero expansion pack, which includes eight more heroes will also be included in that price.
For more information about dungeon Roll visit: http://www.kickstarter.com/projects/michaelmindes/dungeon-roll-a-dicey-dungeon-delve?ref=card